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Consider the total ionic equation below. 2NH+2OH+2H+SO4-->2NH4+2H2O+SO4 what are the spectator ions in this equation?

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Answer:

The NH⁺₄ and SO₄²⁻ are spectator ions.

Step-by-step explanation:

Chemical equation:

NH₄OH(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq) + H₂O(l)

Balanced Chemical equation:

2NH₄OH(aq) + H₂SO₄(aq) → (NH₄)₂SO₄(aq) + 2H₂O(l)

Ionic equation:

2NH⁺₄(aq) + 2OH⁻(aq) + 2H⁺(aq) + SO₄²⁻(aq) → 2NH⁺₄ (aq) + SO₄²⁻(aq) + 2H₂O(l)

Net ionic equation:

2OH⁻(aq) + 2H⁺(aq) → 2H₂O(l)

The NH⁺₄ and SO₄²⁻ are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

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