Question

2. Find the vertex of y = 3x2 - 4x + 10.

Answer 1

(2/3,26/3)

Explanation:

The given parabolic equation is
`y=3x^(2) -4x+10`.

The vertex of a parabola ( if it's axis is parallel to y-axis )
`y=ax^(2) +bx+c` is given by
`((-b)/(2a),(4ac-b^(2))/(4a))`.

So, for the given parabola
`a=3,b=-4,c=10`.

The vertex is
`((-(-4))/(2*3),(4*3*10-(-4)^(2))/(4*3))`

∴ The vertex is given by
`((2)/(3),(26)/(3))`.