Question

A conductor possesses a positive charge of 3.2x 10-19 C. How many electron does it have in excess or deficit (e = 1.60 x 10-19C)

Answer 1

The no of electrons it have in deficit=1.60

Given:

Charge possessed by a conductor =
`3.2 * 10^(-19) C`

Charge of an electron=
`1.6 * 10^(-19) C`

To find:

Amount of electrons in excess or deficit

Step by Step Explanation:

Solution;

Formula used for calculating electrons in excess or deficit is given as

Electrons in excess or deficit= Normal electron charge- Charge of the conductor

Also we know Charge of Conductor
`=3.2 * 10^(-19) C` and Electron charge
`=1.6 * 10^(-19) C`

Substitute these values in the above equation we get

Electrons in excess or deficit=
`1.60 * 10^(-19) \mathrm{C}-3.2 * 10^(-19) \mathrm{C}`

= -1.60

Result:

Hence, it has a deficit of 1.60 electrons.