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Rewrite (x + 3)^2 – 3(x + 3) - 10 as the product of two binomials​

2 Answers

1 vote

Answer:

(X+2) and (X-5)

Step-by-step explanation: (X+3)*x-3(X+3)-10

=(X*2+6X+9)-(3X+9)-10

=X*2+6X+9-3X-9-10

=X*2+3X-10

X=(-b+/-(b*2-4ac)*1/2)/2a

a=1, b=3, c=-10

=-3+/-((3)*x-4(1)9-10))*1/2/2(1)

=-3+/-(9+40)/2

=(-3+/-7)2

Therefore 1. (-3-7)/2, and 2. ((-3+7))/2

1. -10/2=-5, X=-5 therefore (X+5)

2. (4/2)=2, X=2 therefore (X-2)

User Nitind
by
7.8k points
3 votes

Answer:

Explanation:

(x + 3)^2 – 3(x + 3) - 10 = (x + 3) (x + 3) – 3(x + 3) - 10

= (x + 3) [ (x+ 3) - 3 ] -10

= (x + 3 ) [ x + 3 - 3 ] - 10

= (x + 3) * x - 10 = x² + 3x -10

= x² -2x + 5x -10

= x ( x - 2) + 5 (x- 2)

= (x-2) (x+5)

User Timestee
by
8.7k points

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