Answer:
12
Explanation:
f(x)=x+3
g(x)=x^2-x
[f(x)+g(x)]=[x+3]+[x^2-x]
[f(x)+g(x)]=x+3+(x^2)-x
x and -x will be cancelled; hence
[f(x)+g(x)]=x^2+3
f(x)+g(x)=(f+g)(X)
(f+g)(x)=x^2+3
(f+g)(-3)=(-3^2)+3
(f+g)(-3)=9+3
(f+g)(-3)=12
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