Question

A steel ball rolls with constant velocity on a tabletop 0.950 m high. It rolls off and hits the ground 0.352 m from the edge of the table

C) What is the final velocity of the object in the vertical direction?

Answer 1

4.3 m/s

Step-by-step explanation:

In order to find the final velocity of the ball, we can just analyze its vertical motion.

In fact, the ball is in free fall along the vertical direction: this means that it has a constant acceleration, so we can use the following suvat equation

`v^2-u^2=2as`

where

v is the final vertical velocity

u is the initial vertical velocity

a is the acceleration

s is the displacement

In this problem, we know:

u = 0 (the ball starts from rest)

`a=g=9.8 m/s^2` is the acceleration of gravity (taking downward as positive direction)

s = 0.950 m (the height of the tabletop)

Solving for v,

`v=√(u^2+2as)=√(0+2(9.8)(0.950))=4.3 m/s`