Question

A fireman, d = 50.8 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 33.3 ◦ above the horizontal. 50.8 m 44 m/s 33.3 above the horizontal.

If the speed of the stream as it leaves the hose is 44 m/s, at what height will the stream of water strike the building?
The acceleration due to gravity is 9.8 m/s 2 . Answer in units of m.

Answer 1

Total height at which stream can strike building is 24.02 m

Step-by-step explanation:

Given data:

velocity of stream of water v = 44 m/s

Projection angle 33.3 degree

distance between fireman and building is 50.8 m

component of velocity is

`v_x = vcos 33.3\ degree`

= 44 cos 33.3 = 36.775 m/s

`v_y = 44 sin 33.3  = 24.17 m/s`

time taken stream to reach building is

`t =(d)/(v_x) = (50.8)/(36.77) = 1.381 sec`

Hence, the vertical distance covered by stream in time 1.381 sec iis

`s = v_y t - 0.5 gt^2`

`= 24.17* 1.38 - 0.5 * 9.8* 1.38^2`

s = 24.02 m

therefore, total height at which stream can strike building is 24.02 m