Question

A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21.0 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 730. N. At the top of the loop, the rider is upside down and moving, and the sensor reads 360. N. What is the speed of the rider at the top of the loop?

Answer 1

The speed of the rider at the top of the loop 17.53 m/s.

Step-by-step explanation:

Given that,

Radius = 21.0 m

Weight = 730 N

Normal force at the top = 360 N

We need to calculate the mass

Using formula

`W = mg`

`m = (W)/(g)`

Put the value into the formula

`m=(730)/(9.8)`

`m=74.4\ kg`

We need to calculate the speed of the rider at the top of the loop

Using balance equation

`N+mg=(mv^2)/(r)`

`v^2=(r(N+mg))/(m)`

Put the value into the formula

`v=\sqrt{(21.0*(360+74.4*9.8))/(74.4)}`

`v=17.53\ m/s`

Hence, The speed of the rider at the top of the loop 17.53 m/s.