Question

Ajet traveling at 78 m/s accelerates at 23 m/s2 for 6.00 s. What is its final velocity?

Answer 1

216 m/s

Step-by-step explanation:

The jet is moving with uniform accelerated motion, so we can use the following suvat equation:

`v=u+at`

where

v is the velocity at time t

u is the initial velocity

a is the acceleration

For the jet in the problem,

u = 78 m/s is the initial velocity

`a=23 m/s^2` is the acceleration

Substituting t = 6.0 s, we find the final velocity:

`v=78 + (23)(6.0)=216 m/s`