Question

A crate of 45.2-kg tools rests on a horizontal floor. You exert a gradually increasing horizontal push on it and observe that the crate just begins to move when your force exceeds 321 N . After that you must reduce your push to 205 N to keep it moving at a steady 22.3 cm/s . Part A What is the coefficient of static friction between the crate and the floor? μsμ s = nothing Request Answer Part B

Answer 1

μ = 0.725

Step-by-step explanation:

This problem refers to Newton's second law.

F = ma

Let's write the equations on each axis

Y Axis

N-W = 0

N = W

N = mg

X axis

F-fr = ma

With the body not started moving its acceleration is zero

F-fr = 0

F = fr

The friction force equation is

fr = μ N

fr = μ m g

Let's replace and calculate

F = μ m g

μ = F / mg

μ = 321 /45.2 9.8

μ = 0.725