Question

You have an unknownthat contains only one cation (it is oneof the twelve from this experiment).Your solution is colorless and odorless. Treatment with HCl producesawhite precipitate.Treatment with H2SO4 produces a white precipitate. Treatment with NaOHproducesa white precipitate that dissolves when excess NaOHis added.What isthe identity of your cation

Answer 1

Your cation is Pb2+

Step-by-step explanation:

This is the explanation by chemical reactions

HCl (l) ----> H+(aq) + Cl-(aq)

Pb2+(aq) + 2Cl-(aq) ---> PbCl2 (s) ↓

H2SO4 (l) ----> 2H+ (aq) + SO4-2(aq)

Pb2+(aq) + SO4-2(aq) ---> PbSO4 (s) ↓

NaOH (l) ---> Na+(aq) + OH-(aq)

Pb2+(aq) + 2OH-(aq) ---> Pb(OH)2 (s) ↓

If the reaction takes place in a strong alkaline medium, lead hydroxide dissolves in excess of base