Answer:
Option D
Explanation:
Given that the BLS reported in February 2012 that the labor force participation rate in the United States was 63.7%
Let P = 63.7% = 0.637
Sample size n=120
Sample proportion p will be normal with mean = 0.637 and
std error =

required probability
= the probability that the proportion of people who are in the labor force is greater than 0.65
=

APproximately option D is right.