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A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds. A) .4893 B) .0107 C) .9893 D) .5107

User Fsdf Fsd
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Answer: B) 0.0107

Explanation:

As per given , we have


\mu=440\ \text{seconds}\\\\\sigma=50\text{ seconds}

Let x be the random variable that represents the time for this event for boys in secondary school .

z-score =
z=(x-\mu)/(\sigma)

z-score for x= 325 ,
z=(325-440)/(50)=-2.3

Required probability :
P(z<-2.3)=1-P(z<2.3)=1-0.9892759\\\\=0.0107241\approx0.0107

Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds = 0.0107

User Alexander Oh
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