Question

Suppose there are 5x 10 to the power of bacteria in 2 L of water. How many bacteria are there in 5 L of water?

Answer 1

`12.5 x^(10)` number of bacteria

Explanation:

given as :

The Number of Bacteria in 2 L of water =
`5 x^(10)`

∵ 2 L of water have =
`5 x^(10)` number of bacteria

So 1 L of water have =
`(5 x^(10))/(2)` number of bacteria

∴ 5 L of water have =
`(5 x^(10))/(2)` × 5 number of bacteria

=
`12.5 x^(10)` number of bacteria

Hence in 5 L of water ,
`12.5 x^(10)` number of bacteria available Answer