Answer:
Line 1 and line 2 are neither parallel nor perpendicular
Line 1 and 3 are perpendicular to each other
Line 2 and line 3 are neither parallel nor perpendicular
Explanation
Given the equations of the line
Line 1: 4x-6y= -6
Line 2: -3y=2x+5
Line 3: y= -3/2x-5
Before we can know which line is parallel or perpendicular to each other, we need to find their slope first
For line 1:
4x-6y= -6
Write in standard form y = mx+c
-6y = -4x - 6
Divide through by -6
-6y/-6 = -4x/-6 - 6/-6
y = 2/3 x + 1
The slope of line 1 is 2/3
For line 2:
-3y=2x+5
Divide through by -3
-3y/-3 =2x/-3 + 5/-3
y = -2/3 x - 5/3
The slope of this line is -2/3
For line 3:
y= -3/2x-5
this is already written in standard format. The slope of this line is -3/2
Note that for two lines to be parallel, they must have the same slope
For two lines to be perpendicular, the product of their slope must be -1
For line 1 and line2, we can see that their slope are not the same and the product is not -1, hence both lines are neither parallel nor perpendicular
For line 1 and line 3, we can see that their slope are not the same but the product of their slope is -1 (2/3 * -3/2 = -1), hence both lines are perpendicular.
For line 2 and line 3, we can see that their slope are not the same and the product is not -1, hence both lines are neither parallel nor perpendicular