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Line 1: 4x-6y= -6 Line 2: -3y=2x+5 Line 3: y= -3/2x-5 Are line 1 and 2: parallel, perpendicular, or neither? Are line 1 and 3: parallel, perpendicular, or neither? Are line 2 and 3: parallel, perpendicular, or neither?

User Berik
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Answer:

Line 1 and line 2 are neither parallel nor perpendicular

Line 1 and 3 are perpendicular to each other

Line 2 and line 3 are neither parallel nor perpendicular

Explanation

Given the equations of the line

Line 1: 4x-6y= -6

Line 2: -3y=2x+5

Line 3: y= -3/2x-5

Before we can know which line is parallel or perpendicular to each other, we need to find their slope first

For line 1:

4x-6y= -6

Write in standard form y = mx+c

-6y = -4x - 6

Divide through by -6

-6y/-6 = -4x/-6 - 6/-6

y = 2/3 x + 1

The slope of line 1 is 2/3

For line 2:

-3y=2x+5

Divide through by -3

-3y/-3 =2x/-3 + 5/-3

y = -2/3 x - 5/3

The slope of this line is -2/3

For line 3:

y= -3/2x-5

this is already written in standard format. The slope of this line is -3/2

Note that for two lines to be parallel, they must have the same slope

For two lines to be perpendicular, the product of their slope must be -1

For line 1 and line2, we can see that their slope are not the same and the product is not -1, hence both lines are neither parallel nor perpendicular

For line 1 and line 3, we can see that their slope are not the same but the product of their slope is -1 (2/3 * -3/2 = -1), hence both lines are perpendicular.

For line 2 and line 3, we can see that their slope are not the same and the product is not -1, hence both lines are neither parallel nor perpendicular

User JerMah
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