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A railroad handcar is moving along straight, frictionless tracks with negligible air resistance. In the following cases, the car initially has a total mass (car and contents) of 200 kg and is traveling east with a velocity of magnitude 5.40 m/s . Find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.

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Answer:

The final velocity of the car is 6.06 m/s in east.

Step-by-step explanation:

Given that,

Total mass = 200 kg

Velocity = 5.40 m/s

Suppose we find the relative to the initial motion of the car

An object with the mass of 22.0 kg is thrown backward out of the car with a speed of 5.40 m/s relative to the initial motion of the car

We need to calculate the final velocity of the car

Using formula of relative motion


v=(vm)/(m-m_(1))

Put the value into the formula


v=(5.40*200)/(200-22)


v=6.06\ m/s

Hence, The final velocity of the car is 6.06 m/s in east.

User Maxim Vakurin
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