Question

Mr. Howard is a student teacher at the local junior high. His first‐period class of 40 students averaged 96% on a recent test. His second‐period class of 20 students averaged 90% on the same test. What was the combined average for both classes?

Answer 1

94%

Explanation:

Mr. Howard is a student teacher at the local junior high.

• First period class of 40 students averaged = 96%
• Second period class of 20 students averaged = 90%

on same test.

Total score for first period class test = 96% of 40

= 38.4

Total score for second period class test = 90% of 20

= 18

`\text{Combined average score }=\frac{\text{Total score of both test}}{\text{Total number of students}}`

`\text{Combined average score }=(38.4+18)/(40+20)* 100`

`=94\%`

Hence, the combined averaged test score for both classes is 94%

Answer 2

The combined average is 94%

Explanation:

for first period, number of students =40

average =96%

for second period, no of students =20

average =90%

but
`average = (sum of scores)/(no of students)`

let
`S_1` =sum of students for the first period

`S_2` =sum of students for the second period

for first period;

`(S_(1) )/(40) =96%`

`S_(1)= 96*40=3840`

for second period,

`(S_(2) )/(20) =90%`

`S_(1)= 90*20=1800`

therefore the combined average =
`(S_1+S_2)/(40+20)`

that is
`(3840+1800)/(40+20)`
`= 94%`

so combined average is 94%