For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have the following equation:
![y = \frac {1} {2} x-7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bdyu1ne5uft8mfau17z8xxutehb6xg6ilx.png)
So:
, the slope is positive
![b = -7](https://img.qammunity.org/2020/formulas/mathematics/high-school/986ld7144n6dq69yumqv6jy0vujfmge3t5.png)
For the graph, we place the point on the coordinate axis:
![(x, y) :( 0, -7)\\(x, y) :( 1, - \frac {13} {2})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tj78s3fp87wwcirosfbz4t3bjyded05cun.png)
We draw the line!
The graphic is attached.
ANswer:
, the slope is positive
![b = -7](https://img.qammunity.org/2020/formulas/mathematics/high-school/986ld7144n6dq69yumqv6jy0vujfmge3t5.png)