Answer:
The magnitude of the torque is 263.5 N.
Step-by-step explanation:
Given that,
Applied force = 31 N
Distance from the axis = 8.5 m
She applies her force perpendicularly to a line drawn from the axis of rotation
So, The angle is 90°
We need to calculate the torque
Using formula of torque
![\tau=Fd\sin\theta](https://img.qammunity.org/2020/formulas/physics/college/1dk5wtlccm414ll3lmhh03vb2b7ck2ustf.png)
Where, F = force
d = distance
Put the value into the formula
![\tau=31*8.5\sin90](https://img.qammunity.org/2020/formulas/physics/college/xdi5t25kl982ob6t0rsqc3cfacufgilvl1.png)
![\tau= 263.5\ N](https://img.qammunity.org/2020/formulas/physics/college/u61uhbqayj0bpad19wd4cogroqg1h5tcvc.png)
Hence, The magnitude of the torque is 263.5 N.