Step-by-step explanation:
It is given that,
Mass of Adolf,
![m_1=120\ kg](https://img.qammunity.org/2020/formulas/physics/college/j5ixovuc2nozy158gfwg3z4wwx7637we2z.png)
Mass of Ed,
![m_2=70\ kg](https://img.qammunity.org/2020/formulas/physics/college/cv5eoktib3nxj0rqphp6izum8tbioqrngs.png)
Adolf swings upward to a height of 0.52 m above his starting point. Initially both men are at rest. Their momentum will remain conserved.
Firstly, finding the speed of Adolf by using the conservation of energy as :
![mgh=(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/high-school/q4tq2cl01gkg6gs57to64i8cr5r68e7rv7.png)
![v=√(2gh)](https://img.qammunity.org/2020/formulas/physics/high-school/o5ivb5txniqdehqlo3egp2mzj0c36o0vo8.png)
![v=√(2* 9.8* 0.52)](https://img.qammunity.org/2020/formulas/physics/college/gppobg5mex69m4r65hf6gkmxd1qrztkvd7.png)
v = 3.19 m/s
Let v' is the speed of Ed. It can be calculated using the conservation of momentum as :
![m_1v+m_2v'=0](https://img.qammunity.org/2020/formulas/physics/college/fa7nafnrz91b2da4z8zevg3xbveypujg0b.png)
![v'=-(m_1v)/(m_2)](https://img.qammunity.org/2020/formulas/physics/college/22ncjortlh1ja7ql01xm14cekoj38imq1m.png)
![v'=-(120* 3.19)/(70)](https://img.qammunity.org/2020/formulas/physics/college/k7c2l7v4ogcra08s0janvalnue5yrwaq3x.png)
v' = -5.46 m/s
Let H is the height above which Ed rise. It can be calculated using the conservation of energy again as:
![H=(v^2)/(2g)](https://img.qammunity.org/2020/formulas/physics/college/e9xi7h6j8h5kzjwkzraigfkgixwog1ur1r.png)
![H=((-5.46)^2)/(2* 9.8)](https://img.qammunity.org/2020/formulas/physics/college/4p5et9vzc75hrff1fl4czgb8hhjco0tdpj.png)
H = 1.52 meters
So, Ed will rise to a height of 1.52 meters. Hence, this is the required solution.