Answer:
The speed of the car is 7.84 m/s
Solution:
As per the question:
Length of the bridge, l = 5.0 m
Distance, d = 2 m
Now,
Time taken by the car to reach 2 m lower is given by the kinematic eqn:
![d = ut + (1)/(2)at^(2)](https://img.qammunity.org/2020/formulas/physics/college/32o6p3txzojclza1qecny6qorfas1y0n31.png)
where
u = initial velocity = 0 m/s
t = time taken
a = g =
![9.8\ m/s^{}](https://img.qammunity.org/2020/formulas/physics/college/x8yalvfi07xfurv9hujcthpqmboiihjry2.png)
Now,
![2 = 0.t + (1)/(2)* 9.8* t^(2)](https://img.qammunity.org/2020/formulas/physics/college/h932ulezwtrnt6ey91mtciy3a45nk776ll.png)
![t = 0.638\ s](https://img.qammunity.org/2020/formulas/physics/college/enjjya6ghhbc5jdzavdhpc010k4bqh4w8a.png)
Now, we kow that the car will cover the distance equal to the length of the bridge, i.e., 5 m
Speed of the car is given by:
![v = (distance\ covered)/(time\ taken)](https://img.qammunity.org/2020/formulas/physics/college/1m7oc4is19djs2e3ryfg1v5excfkfllqar.png)
![v = (5.0)/(0.638) = 7.84\ m/s](https://img.qammunity.org/2020/formulas/physics/college/in9r6waakhxr43tyxr5rt3mmtek242ijlv.png)