Question

Two parallel paths 20 m apart run east–west through the woods. Brooke walks east on one path at 6 km/h, while Jamail walks west on the other path at 7 km/h. If they pass each other at time ????=0, how far apart are they 11 s later, and how fast is the distance between them changing at that moment? (Use decimal notation. Give your answer to three decimal places.)

Answer 1

46.218 m

Step-by-step explanation:

Distance = Speed × Time

`Distance=(6)/(3.6)* 11=(55)/(3)\ m`

Distance traveled by Brooke is
`(55)/(3)\ m`

`Distance=(7)/(3.6)* 11=(70)/(3)\ m`

Distance traveled by Jamail is
`(70)/(3)\ m`

From Pythagoras theorem

`s=\sqrt{20^2+\left((125)/(3)\right)^2}\\\Rightarrow s=46.218\ m`

The distance between Brooke and Jamail after 11 seconds is 46.218 m