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If 3.50 mol of ethane, CzH6, undergo combustion according to the unbalaced equation given of oxygen requires ?

How many moles of each product formed?

If 3.50 mol of ethane, CzH6, undergo combustion according to the unbalaced equation-example-1
User Maloney
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1 Answer

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The Balance Chemical equation for said reaction is as follow,

C₂H₆ + 3.5 O₂ → 2 CO₂ + 3 H₂O

Or,

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

According to equation,

2 moles of Ethane react completely with = 7 moles of Oxygen

So,

4.20 moles of Ethane will react with = X moles of Oxygen

Solving for X,

X = (4.20 mol × 7 mol) ÷ 2 mol

X = 14.7 moles of Oxygen

Result:

14.7 moles of Oxygen are required to react with 4.20 moles of Ethane for complete reaction.

User KitAndKat
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