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El sargento Conejero toma el sol en su colchoneta, de 2 m2 de superficie, flotando en el agua de la piscina (d = 1 g/cm3 ). Si observamos que ésta se hunde 2,7 cm, ¿cuál es el peso del sargento? (Desprecia el peso de la colchoneta).

User NovaJoe
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1 Answer

6 votes

Answer:

W = 529.2 N

Step-by-step explanation:

We can solve this problem using the translational equilibrium equation, where the forces are the weight of the sergeant and the thrust of the water given by Archimedes' principle

B - W = 0

where the thrust is

B = ρ g V_liquid

The volume of the displaced liquid is

V = A h

we substitute

ρ g A h = W

We reduce the magnitudes to the SI system

h = 2.7 cm = 0.027 m

ρ = 1 g / cm3 = 1000 kg / m³

let's calculate

W = 1000 9.8 2 0.027

W = 529.2 N

User Harden
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