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A person walks in the following pattern: 3.1 km north, then 2.4 km west, and finally 5.2 km south. a) Sketch the vector diagram that represents this motion. b) How far and in what direction would a bird fly in a straight line from the same starting point to the same final point?

1 Answer

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Answer:


d = 3.19 km

direction is given as


\theta = 41.2 degree South of West

Step-by-step explanation:

Part b)

displacement is given as


d_1 = 3.1 \hat j


d_2 = 2.4 \hat i


d_3 = 5.2(-\hat j)

now we will have


d = d_1 + d_2 + d_3


d = 2.4 \hat i + (3.1 - 5.2)\hat j


d = 2.4 \hat i - 2.1 \hat j

total displacement is given as


d = √(2.4^2 + 2.1^2)


d = 3.19 km

direction is given as


tan\theta = (-2.1)/(2.4)


\theta = 41.2 degree South of West

User Anderson Green
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