Question

A vanadium bolt gives up 1124 J of energy as its temperature drops 25 k if the bolts mass is 93 g what is its specific heat

Answer 1

0.483 J/(gK)

Step-by-step explanation:

When a sample of a material of mass m gives off an amount of energy Q, the temperature of the material decreases by
`\Delta T`, according to the equation :

`Q=mC_s \Delta T`

where
`C_s` is the specific heat capacity of the material.

In this problem, we have:

m = 93 g is the mass of the vanadium bolt

`Q = -1124 J` is the amount of energy given off by the vanadium bolt

`\Delta T = -25 K` is the change in temperature of the vanadium

Solving the equation for
`C_s`, we find the specific heat capacity of vanadium:

`C_s = (Q)/(m \Delta T)=(-1124)/((93.0)(-25))=0.483 J/(gK)`