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A vanadium bolt gives up 1124 J of energy as its temperature drops 25 k if the bolts mass is 93 g what is its specific heat

User Avi Kapuya
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1 Answer

3 votes

Answer:

0.483 J/(gK)

Step-by-step explanation:

When a sample of a material of mass m gives off an amount of energy Q, the temperature of the material decreases by
\Delta T, according to the equation :


Q=mC_s \Delta T

where
C_s is the specific heat capacity of the material.

In this problem, we have:

m = 93 g is the mass of the vanadium bolt


Q = -1124 J is the amount of energy given off by the vanadium bolt


\Delta T = -25 K is the change in temperature of the vanadium

Solving the equation for
C_s, we find the specific heat capacity of vanadium:


C_s = (Q)/(m \Delta T)=(-1124)/((93.0)(-25))=0.483 J/(gK)

User Amsheer
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