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The electric potential, VVV, in volts, between two metal plates a distance of ddd millimeters from the left plate is given by the equation above when 0 \le d \le 150≤d≤150, is less than or equal to, d, is less than or equal to, 15. By how many millimeters does the distance from the left plate increase for the potential to increase by 111 volt? Answer:

User FrancMo
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2 Answers

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V is the voltage or the potential difference between the plates, usually expressed in volts.

Infinite parallel plates have a uniform electric field between them.

So V = 245 (V/m) * 0.0037 (m) = 0.9065 volts

User Sunspawn
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3 votes

Answer:

The distance from the left plate increases by 3 mm for the potential to increase by 1 volt.

Explanation:

The complete Question is

V = -2.6 + (d/3)

The electric potential, V, in volts, between two metal plates a distance of d millimetres from the left plate is given by the equation above when 0≤d≤15. By how many millimetres does the distance from the left plate increase for the potential to increase by 1 volt?

Mathematically, the derivative of d with respect to V is equal to the ratio of small changes in d divided by small changes V.

(dd/dV) = (Δd/ΔV)

Δd = (dd/dV) × ΔV

V = -2.6 + (d/3)

(d/3) = V + 2.6

d = 3V + 7.8

(dd/dV) = 3

Δd = (dd/dV) × ΔV

(dd/dV) = 3 mm/volt

ΔV = 1 volt

Δd = 3 × 1 = 3 mm

Hope this Helps!!!!

User Mingyu Jeon
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