Answer:
The distance from the left plate increases by 3 mm for the potential to increase by 1 volt.
Explanation:
The complete Question is
V = -2.6 + (d/3)
The electric potential, V, in volts, between two metal plates a distance of d millimetres from the left plate is given by the equation above when 0≤d≤15. By how many millimetres does the distance from the left plate increase for the potential to increase by 1 volt?
Mathematically, the derivative of d with respect to V is equal to the ratio of small changes in d divided by small changes V.
(dd/dV) = (Δd/ΔV)
Δd = (dd/dV) × ΔV
V = -2.6 + (d/3)
(d/3) = V + 2.6
d = 3V + 7.8
(dd/dV) = 3
Δd = (dd/dV) × ΔV
(dd/dV) = 3 mm/volt
ΔV = 1 volt
Δd = 3 × 1 = 3 mm
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