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What is the equation of the following line written in slope-intercept form -2/3 and -1/-4? y = -11x - 7 y = -7x + 11 y = -7x - 11

User Jorge Luis
by
6.4k points

1 Answer

4 votes

Answer:


y=-7x-11

Explanation:

Given:

The two points on the line are
(-2,3) and
(-1,-4).

The slope of the line joining two points
(x_(1),y_(1)) and
(x_(2),y_(2)) is given as:


Slope,m=(y_(2)-y_(1))/(x_(2)-x_(1))

Here,
x_(1)=-2,y_(1)=3,x_(2)=-1,y_(2)=-4


m=(-3-4)/(-1-(-2))=(-7)/(-1+2)=(-7)/(1)=-7

Equation of line with a point
(x_(1),y_(1)) and slope
m is given as:


y-y_(1)=m(x-x_(1))

Plug in -2 for
x_(1), 3 for
y_(1) and -7 for
m. This gives,


y-3=-7(x-(-2))\\y-3=-7(x+2)\\y-3=-7x-(7* 2)\\y-3=-7x-14\\y=-7x-14+3\\y=-7x-11

Therefore, the equation of the line in vertex form is
y=-7x-11.

User Mark Hannel
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6.3k points