A rocket is launched straight up from the top of a 125-foot building with an initial velocity of 128 feet per second. Find the time interval when the rocket's height exceeds 317 feet.

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asked Jul 13, 2020 144k views

4 votes

A rocket is launched straight up from the top of a 125-foot building with an initial velocity of 128 feet per second. Find the time interval when the rocket's height exceeds 317 feet.

Mathematics
middle-school

Angolao asked

by Angolao

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1 Answer

3 votes

Answer:

About 2.5 seconds

Explanation:

317 divided by 128 equals 2.47, rounded off to 2 sig. figs. to 2.5

Kelan answered Jul 17, 2020

by Kelan

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