(10,y) and (3,4) m"-2/7

Question

asked Oct 3, 2020 67.8k views

1 Answer

Shlomi Hassid · Answer 1 · 2020-10-09T01:06:53+0000

For this case we have to by definition, given two points through which a line passes:

$(x_ {1}, y_ {1})$ and
$(x_ {2}, y_ {2})$

We can find the slope using the following formula:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

In this case we have the slope and we must find the "y" coordinate of one of the points.

We have:

$(x_ {1}, y_ {1}): (3,4)\\(x_ {2}, y_ {2}) :( 10, y)\\m = - \frac {2} {7}$

Substituting we have:

$m = \frac {y_ {2} -4} {10-3} = \frac {y-4} {7}$

So:

$- \frac {2} {7} = \frac {y-4} {7}\\\frac {-2} {7} = \frac {y-4} {7}$

Thus:

$y_ {2} -4 = -2\\y_ {2} = - 2 + 4\\y_ {2} = 2$

Thus, the "y" coordinate of point 2 is: 2

Answer:

$y_ {2} = 2$