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The length and width of a rectangle are consecutive odd integers. The perimeter is 88 meters. Find the length and width.

User Snorkpete
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Final answer:

The rectangle has a width of 21 meters and a length of 23 meters, since its dimensions are consecutive odd integers and its perimeter is 88 meters.

Step-by-step explanation:

To find the length and width of a rectangle where the dimensions are consecutive odd integers and the perimeter is 88 meters, we first write the formula for the perimeter of a rectangle:

P = 2l + 2w

Since the length (l) and width (w) are consecutive odd integers, we can express the width as w and the length as w + 2 (since the next odd integer after an odd number w is w + 2). Substituting w and w + 2 into the formula gives us:

88 = 2(w + 2) + 2w

Expanding the equation, we have:

88 = 2w + 4 + 2w

Combining like terms:

88 = 4w + 4

Subtracting 4 from both sides:

84 = 4w

Divide both sides by 4:

w = 21

So the width is 21 meters. Then the length is w + 2 = 23 meters.

To summarize, the width of the rectangle is 21 meters, and the length is 23 meters.

User Rick Wayne
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