Question

What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6 ?

Answer 1

y=1/2x-2

Explanation:

y=-2x-6

slope = -2x

reciprocal slope = I/2x

equation of line = y-y1=m(x-x1)

y-1=1/2(x-6)

y-1=1/2x-3

y=1/2x-2