Answer:
Given that
u = 13 m/s
h= 23 m
a) horizontally
We know that acceleration due top gravity is in vertical direction.
v²=u'²+ 2 g h ( u'= 0 )
v² = 2 x 9.81 x 23
v= 21.24 m/s ( vertical direction)
In the horizontal direction
u = 13 m/s
The resultant velocity
V²=v²+u²
V²=21.24²+13²
V= 24.91 m/s
(b) vertically straight up
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
c)vertically straight down.
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s