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Consider two object has mass m1=5.0kg m2=0.5kg and the specific heat c1=c2=4200j/kg oc respectively assume that first object has temperature 20oc and second object has temperature 90oc After they place these two object touch each other determine the mixture temperature of the substance

1 Answer

6 votes

Answer:
T=26.36^(\circ)C

Step-by-step explanation:

Given

mass of the first object
m_1=5\ kg

mass of the second object
m_2=0.5\ kg

specific heat of the two is
c_1=c_2=4200\ J/kg/^(\circ)C

The temperature of the first
T_1=20^(\circ)

The temperature of the second
T_2=90^(\circ)

Heat flows from high temperature to low temperature

Suppose T is the common temperature


m_1c_1(T-T_1)=m_2c_2(T_2-T)\\5* 4200* (T-20)=0.5* 4200* (90-T)\\5T-100=45-0.5T\\5.5T=145\\T=26.36^(\circ)C

User Alejandro Duarte
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