Answer:

Explanation:
According to the probabilistic relationship between the exponential distribution and the Poisson distribution, which expresses that if the time between events is exponential with mean m (rate L=1/m) then the number of events of a t time is Poisson with a L*t parameter. Therefore, the probability mass function is given by,

Where,

m: mean
In this case as we have that the mean is 3 (that is m=3), then the probability mass function of X is:
