Question

A 21 kg block slides down a frictionless slope which is at angle θ = 25◦ . Starting from rest, the time to slide down is t = 1.51 s. The acceleration of gravity is 9.8 m/s 2 . 21 kg s 25◦ What total distance s did the block slide? Answer in units of

Answer 1

s = 4.71 m

Step-by-step explanation:

given,

mass of the block = 21 kg

angle θ = 25◦

time to slide = 1.51 s

acceleration = 9.8 m/s²

distance = ?

acceleration = a sin θ

= 9.8 sin 25° = 4.14 m/s²

`s = ut + (1)/(2)at^2`

`s = (1)/(2)* 4.14* 1.51^2`

s = 4.71 m

hence, the distance traveled by the block = 4.71 m