Question

URGENT, DUE VERY SOON

A coordinate plane from negative 8 to 8 along the x-axis and from negative 7 to 7 along the y-axis. Which steps should be used to graph the equation y – 4 = y minus 4 equals StartFraction one-third EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)? 1. Plot the point (2, 4). 2. From that point, count left 3 units and down 1 unit and plot a second point. 3. Draw a line through the two points. 1. Plot the point (2, 4). 2. From that point, count left 1 unit and down 3 units and plot a second point. 3. Draw a line through the two points. 1. Plot the point (–2,4). 2. From that point, count left 3 units and down 1 unit and plot a second point. 3. Draw a line through the two points. 1. Plot the point (–2,4). 2. From that point, count left 1 unit and down 3 units and plot a second point. 3. Draw a line through the two points.

Answer 1

C

Explanation:

I did it

Answer 2

1. Plot the point (–2,4).

2. From that point, count left 3 units and down 1 unit and plot a second point.

3. Draw a line through the two points.

Explanation:

Given:

The equation is:
`y-4=(1)/(3)(x+2)`

Express this in the standard form,
`y=mx+b`

Where,
`m` is the slope of the line and
`b` is the y-intercept.

`y-4=(1)/(3)((x+2)\\y=(1)/(3)((x+2)+4\\y=(1)/(3)x+(2)/(3)+4\\y=(1)/(3)x+(14)/(3)`

So, the slope is
`(1)/(3)` and y-intercept is
`(14)/(3)`.

Now, for
`x=-2,y=(1)/(3)* -2+(14)/(3)=4`

So, first we plot the point
`(-2,4)`.

Since, the slope is
`(1)/(3)`, we have to move 3 units to left and then 1 unit down to plot a second point.

Slope is positive, therefore, we have to move left and then down

Lastly, we have to draw a line passing through these two points to graph the equation
`y-4=(1)/(3)(x+2)`.