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Which is equivalent to

16 Superscript three-fourths x ?
Rootindex 4 StartRoot 16 EndRoot Superscript 3x
Rootlndex 4 x StartRoot 16 EndRoot cubed
3 Rootindex 3 StartRoot 16 End Root Superscript 4 x
E
Rootindex 3 x StartRoot 16 End Root Superscript 4

1 Answer

7 votes

Answer:

A)
16^(3)/(4)=\sqrt[4]{16^3}

Explanation:

1) According to Exponents Law, whenever we have a number raised to a fraction this is the same as having a root of its number whose index is the denominator, raised to the numerator.


n^{(a)/(b)}=\sqrt[b]{n^(a)}\\16^{(3)/(4)}=\sqrt[4]{16^(3)}=\sqrt[4]{4096}=\sqrt[4]{2^(12)}=8

Then
16^(3)/(4)=\sqrt[4]{16^3}

User PaFi
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