Question

Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45-m-diameter semicircles. A greyhound can run around these turns at a constant speed of 15 m/s. What is its acceleration in m/s2

and in units of g?

Answer 1

Step-by-step explanation:

It is given that,

Diameter of the semicircle, d = 45 m

Radius of the semicircle, r = 22.5 m

Speed of greyhound, v = 15 m/s

The greyhound is moving under the action of centripetal acceleration. Its formula is given by :

`a=(v^2)/(r)`

`a=((15)^2)/(22.5)`

`a=10\ m/s^2`

We know that,
`g=9.8\ m/s^2`

`a=(10* g)/(9.8)`

`a=1.02\ g`

Hence, this is the required solution.