Answer: 1.27 m/s^2
Step-by-step explanation:
from the question we are given the following
mass of A = 54.5 kg
mass of B = 33.6 kg
mass of A and B = 88.1 kg
velocity of A = 1.51 m/s ( at +x direction )
velocity of B = 2.28 m/s ( at +y direction )
the first diagram below shows the motion of skaters A and B before and after collision
to solve this question we would apply the formula momentum = mass x velocity
momentum of A = 54.5 x 1.51 = 82.3 kgm/s
momentum of B = 33.6 x 2.28 = 76.6 kgm/s
using the momentum obtained above, we rearrange the motion of skaters A and B to form a right angle triangle with the momentum of A on the x axis , momentum of B on the y axis and the unknown momentum of A and B as the hypothenus.
applying Pythagoras theorem momentum of A and B =
![\sqrt{(momentum of A^(2) + momentum of B^(2) )}](https://img.qammunity.org/2020/formulas/physics/high-school/9j34ucxjr4qv93s609qjtvg2umnhkan1ut.png)
therefore momentum of A and B =
![\sqrt{82.3^(2) +76.6^(2) }](https://img.qammunity.org/2020/formulas/physics/high-school/jt37ytwefulyail190bc43e1i0d7thr9k9.png)
= 112.4 kgm/s
recall that momentum = mass x velocity
therefore velocity = momentum / mass
velocity of A and B = 112.4 / 88.1 = 1.27 m/s^2