Question

If an athlete expends 2550. kJ/h, how long does she have to play to work off 1.00 lb of body fat? Note that the nutritional calorie (Calorie) is equivalent to 1 kcal, and one pound of body fat is equivalent to about 4.10 × 103 Calories.

Answer 1

`t=6.73h`

Step-by-step explanation:

Hello,

In this exercise we first must consider that the energy she has to consume in kJ (taking into account the nutritional calorie) to loss 1.00 lb of body fat is:

`4.10x10^3kcal*(4.1858kJ)/(1kcal) =17161.78kJ`

Now, the spent time to lose that amount of energy (which is reflected in the loss of 1.00 lb), we must apply the formula:

`t=(17161.78kJ)/(2550kJ/h)=6.73h`

Best regards.