Answer:

Step-by-step explanation:
From the equation we know that the gravitational potential energy:
.......................(1)
The negative potential indicates a bound state.
where:
M= mass of the earth
m= mass of the object
r= radial distance from the center of the earth
G= universal gracvitational constant=

Given:
m= 4kg
We, have

∵The object is on the earth surface, we have the radius of the earth:

Putting the values in the eq. (1)

