For this case we propose a system of equations:
x: Let the variable representing the age of the first child of the Smiths
y: Let the variable representing the age of the second child of the Smiths
According to the data of the statement we have to:
![x + y = 23\\x * y = 132](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tukkqpb2fe2jjy7vo4h57vf3tzas3gc4ky.png)
From the first equation we have to:
![x = 23-y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eyxlhacxew1vjyxjatfxos9l6438vegukg.png)
We substitute in the second equation:
![(23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lf2qqiv8tkump99phclhtoik0imvpq3b29.png)
We find the solutions by factoring:
We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.
Thus, we have that the factorized equation is:
![(y-11) (y-12) = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ofw51vmm6iupu3oax3d0cb1vdrbzke6vnr.png)
Thus, the solutions are:
![y_ {1} = 11\\y_ {2} = 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hco064fxzmhpzuvtwzqgwct234g1e3lcge.png)
So, we can take any of the solutions:
With
![y = 11](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o9bmlkd6zb209l3swtpnuh32i577dqeryv.png)
Then
![x = 23-11 = 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/obno7bdqhce2tnzkiaikjljm7o8256omj4.png)
Therefore, the ages of the children are 11 and 12 respectively.
Answer:
The ages of the children are 11 and 12 respectively.