Answer:
Explanation:
We are given the following information in the question:
We have to find the equation of line passing through the point (5,5) anfd parallel to the line with slope
.
Since the line is parallel, they will have the same slope.
Thus, slope of line =
![\displaystyle(1)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/7v2vvv0klo3gzay2zkffm6cibolprnk3dm.png)
Point-slope form:
,
where m is the slope of line and
is a point on the line.
Putting all the values, we have the equation of line:
![(y-y_1) = m(x-x_1)\\(y-5) = \displaystyle(1)/(4)(x -5)\\\\4(y-5) = (x-5)\\4y-20 = x -5\\4y-x = -5+20\\4y-x = 15](https://img.qammunity.org/2020/formulas/mathematics/high-school/9lbmy6wrt2r30ig7cezklnobgpiewt4rc7.png)
The above equation is the required equation of the line.