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write the point slope form of the line that passes through (5,5) and is parrallel to a line with a slope of 1/4. include all of your work in your final answer. type your answer in the box provided ?

1 Answer

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Answer:


4y-x = 15

Explanation:

We are given the following information in the question:

We have to find the equation of line passing through the point (5,5) anfd parallel to the line with slope
(1)/(4).

Since the line is parallel, they will have the same slope.

Thus, slope of line =
\displaystyle(1)/(4)

Point-slope form:


(y-y_1) = m(x-x_1),

where m is the slope of line and
(x_1,y_1) is a point on the line.

Putting all the values, we have the equation of line:


(y-y_1) = m(x-x_1)\\(y-5) = \displaystyle(1)/(4)(x -5)\\\\4(y-5) = (x-5)\\4y-20 = x -5\\4y-x = -5+20\\4y-x = 15

The above equation is the required equation of the line.

User Tbolender
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