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Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

B) Only x = 1 is an extraneous solution.
C) Both solutions are extraneous.
D)Neither solution is extraneous.

User Dowhilefor
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2 Answers

1 vote

Answer:D

Explanation:

User Johnnymire
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4 votes

Answer:

Option D)Neither solution is extraneous.

Explanation:

we have


√(11-2x)=\sqrt{x^(2)+4x+4}

we know that

two possible solutions are x=-7 and x=1

Verify each solution

Substitute each value of x in the expression above and interpret the results

1) For x=-7


√(11-2(-7))=\sqrt{-7^(2)+4(-7)+4}


√(25)=√(25)


5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1


√(11-2(1))=\sqrt{1^(2)+4(1)+4}


√(9)=√(9)


3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

User Michael Crook
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