Answer:
![5 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/deprebergm7dhkgyf2cph0sejf7yszrgco.png)
Step-by-step explanation:
Assuming the tension in the rope is the only force acting on the block, then we can use Newton's second law:
![F=ma](https://img.qammunity.org/2020/formulas/physics/middle-school/hoqv0uuwk5hamoxytydy5e8slsjemaiqzz.png)
where
F is the net force on the block
m is the mass of the block
a is its acceleration
The tension in the rope is the only force acting on the block, so
F = T = 10 N
The mass of the block is
m = 2 kg
So, solving for a, we find the acceleration:
![a=(F)/(m)=(10)/(2)=5 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/ypmve7w8yezyma5udfet7mws1s0n2ty0ox.png)