Question

What is the equation of the line that passes through the poilt (-1, 4) and has a
slope of -5?

Answer 1

y=-5x-1

Explanation:

You have to first put it in point-slope form. y-y1=m(x-x1)

The y is 4 and the x is -1.

y-4=-5(x+1)

Now you put it in slope intercept form. y=mx+b.

y-4=-5x-5

Add 4 to both sides

y=-5x-1