Answer: 0.977
Explanation:
Given : The proportion of school’s graduates find a job in their chosen field within a year after graduation : p= 0.53
Let x be the binomial variable that represents the number of students finds a job in his or her chosen field within a year of graduating.
with parameter p = 0.53 n= 5
Using binomial , we have
![P(x)=^nC_xp^x(1-p)^(n-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/go5usnnxzkib641nm6qufyixf9qjuc62cs.png)
Required probability :-
![P(x\geq1)=1-P(x=0)\\\\=1-^5C_0 (0.53)^0(1-0.53)^5\\\\=1-(0.47)^5\\\\=0.9770654993\approx0.977](https://img.qammunity.org/2020/formulas/mathematics/high-school/fde3t2nqvh5de20ydmn88l2iecui2c6vjo.png)
Hence, the probability that among 5 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating = 0.977