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A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. The same cart again traveling at 0.3 m/s collides with a different stationary object. This time the cart is at rest after the collision. In which collision is the impulse on the cart greater? Group of answer choices

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Answer:

Impulse in the first collision is greater

Step-by-step explanation:

u = Initial velocity of cart

v = Final velocity of cart

m = Mass of of cart

First collision

Impulse


J=m(v-u)\\\Rightarrow J=m(0.3-(-0.3))\\\Rightarrow J=m(0.6)

Second collision

Impulse


J=m(v-u)\\\Rightarrow J=m(0-(-0.3))\\\Rightarrow J=m(0.3)

Hence, the impulse in the first collision is greater than the second impact

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