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If the explorer visited the three places and raised her hand when she reached each of them, where would the change in gravitational potential energy of her hand be greater? The summit of Chimborazo, in Ecuador, which is at a distance of 6, 384 km from the Earth's center. The bottom of the Mariana Trench, in the western Pacific ocean, which is nearly 6, 370 km from the center of the arih On the surface of Earth on the Equator line. Same in all cases. Submit

User Brenzo
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2 Answers

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Answer:

The bottom of Mariana trench

Step-by-step explanation:

change in PE = m g h

m and h will remain same for each case.

but g = G M / r^2

r is different for all three case.

which have smallest r, there will be greatest change.

Ans: The bottom of Mariana trench

User Dustydojo
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1 vote

Answer:

Magnitude of gravity will be maximum at the bottom of the Mariana Trench.

Step-by-step explanation:

The acceleration due to gravity always decreases while gaining altitude or going below the surface


g_a=g\left(1-(2h)/(R)\right)


g_d=g\left(1-(d)/(R)\right)

The radius of Earth is 6378.1 km

Height of Chimborazo is 6,263 m


g_a=9.81\left(1-(2* 6.236)/(6378.1)\right)\\\Rightarrow g_a=9.79081\ m/s^2


g_d=9.81\left(1-(10.984)/(6378.1)\right)\\\Rightarrow g_d=9.79310\ m/s^2

It can be seen that the acceleration due to gravity is almost same in both situations.


PE=mgh


PE_c=mg6263


PE_m=mg(-10984)

Hence, the magnitude of gravity will be maximum at the bottom of the Mariana Trench.

At the equator surface h will become zero hence it will not hace gravitational potential energy

User Vincent Han
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